BBS OF 2L Rectangular Stirrups
In this article, I’m going to discuss, how to calculate the cutting length of a rectangular stirrup. Before proceeding with the calculations, let me introduce you to the components of a Stirrup or a Tie. As you can clearly visualize from the above picture, a rectangular stirrup is bent at 3 of its corners by an angle of 90 degrees, and 2 number of 135-degree bends along with 2 number of hooks given at the 4th corner.
Example: Calculate the cutting length of a rectangular stirrup for a beam of Width 230mm & Depth of 300mm. The diameter of the stirrups is given as 8mm with a clear cover of 25mm
Given:
Width of beam = 230 mm.
Depth of beam = 300 mm.
Clear cover = 25 mm.
Diameter of the stirrup = 8 mm
Cutting Length = 2(a + b) + 2(10d) – 3(2d) – 2(3d) ___(1)
Where ‘’a’’ is the c/c distance between the extreme vertical bars of the stirrup along the width of the beam & ‘’b’’ is the c/c distance between the extreme horizontal bars of the stirrup along the depth of the beam.
a = Width – 2(clear cover) – 2(d/2)
= 230 – 2(25) – 2(8/2) = 172mm
b = Depth – 2(clear cover) – 2(d/2)
= 300 – 2(25) – 2(8/2) = 242mm
10d = Hook length = 10 x 8
2d = 90 degree bend = 2 x 8
3d = 135 degree bend = 3 x 8
On substituting these values in eq. 1, we get
Cutting Length = 2(172 + 242) + 2(10 x 8) – 3(2 x 8)
– 2(3 x 8) = 828 + 160 – 48 – 48 = 892mm or 0.89m
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